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創(chuàng)新互聯(lián)Python教程：

編寫一個(gè) Python 程序來查找元組中所有項(xiàng)目的總和。這里，我們使用 Tuple sum 函數(shù)返回所有 Tuple 項(xiàng)的總和。

# Tuple Sum of All Items

numTuple = (20, 40, 65, 75, 80, 220)
print("Tuple Items = ", numTuple)

tupleSum = sum(numTuple)
print("\nThe Sum of numTuple Tuple Items = ", tupleSum)

Tuple Items =  (20, 40, 65, 75, 80, 220)

The Sum of numTuple Tuple Items =  500

尋找元組項(xiàng)之和的 Python 程序

在這個(gè) Python 示例中，for 循環(huán)(用于 numTuple 中的 tup)迭代所有元組項(xiàng)。在循環(huán)(tupleSum = tupleSum + tup)中，我們將每個(gè)元組項(xiàng)添加到 tupleSum 中，并打印相同的內(nèi)容。

# Tuple Sum of All Items

numTuple = (11, 22, 33, 44, 55, 66, 77, 88, 99)
print("Odd Tuple Items = ", numTuple)

tupleSum = 0
for tup in numTuple:
    tupleSum = tupleSum + tup

print("\nThe Sum of numTuple Tuple Items = ", tupleSum)

Odd Tuple Items =  (11, 22, 33, 44, 55, 66, 77, 88, 99)

The Sum of numTuple Tuple Items =  495

Python 程序使用 While 循環(huán)計(jì)算所有元組項(xiàng)的總和。

# Tuple Sum of All Items

numTuple = (25, 45, 65, 75, 95, 125, 256, 725)
print("Odd Tuple Items = ", numTuple)

tupleSum = 0
i = 0

while (i < len(numTuple)):
    tupleSum = tupleSum + numTuple[i]
    i = i + 1

print("\nThe Sum of numTuple Tuple Items = ", tupleSum)

Odd Tuple Items =  (25, 45, 65, 75, 95, 125, 256, 725)

The Sum of numTuple Tuple Items =  1411

在這個(gè) Python Tuple 示例中，我們創(chuàng)建了一個(gè) sumOfTupleItems(numTuple)函數(shù)，該函數(shù)將計(jì)算并返回所有 tuple 項(xiàng)的總和。

# Tuple Sum

def sumOfTupleItems(numTuple):
    tupleSum = 0
    for tup in numTuple:
        tupleSum = tupleSum + tup
    return tupleSum

numTuple = (16, 31, 24, 98, 123, 78, 56, 67, 22)
print("Tuple Items = ", numTuple)

tSum = sumOfTupleItems(numTuple)
print("\nThe Sum of numTuple Tuple Items = ", tSum)

文章題目：Python程序：計(jì)算元組項(xiàng)和
文章位置：http://www.dlmjj.cn/article/dhpiged.html