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1、模糊查詢的陷阱

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- cursor = db.rawQuery("select * from song where song_title like '?%' ", selectionArgs);
這行代碼中由于占位符 ? 在單引號(hào)內(nèi),因此不會(huì)被當(dāng)做占位符,而是對(duì)?進(jìn)行了模糊查找,會(huì)產(chǎn)生類似如下報(bào)錯(cuò):
android.database.SQLite.SQLiteException: bind or column index out of range: handle 0x3418b0
解決方法:
- cursor = db.rawQuery("select * from song where song_title like '" + selectionArgs[0] + "%'", selectionArgs);
2、cursor.getString(0)方法的陷阱
- cursor = db.rawQuery("select song_singer from song group by song_singer having count(*)<2 ", null); 2 cursor.moveToFirst(); 3 for ( int i= 0; i
以上代碼可以正確實(shí)現(xiàn)從在database中返回的cursor中讀取數(shù)據(jù),但以下代碼會(huì)出現(xiàn)問(wèn)題
- cursor = db.rawQuery("select * from song where song_title like '" + selectionArgs[0] + "%'", null); 2 System.out.println(cursor.getString(0));
會(huì)出現(xiàn)類似這個(gè)錯(cuò)誤:android.database.CursorIndexOutOfBoundsException: Index -1 requested, with a size of 1
解決方法:
- cursor = db.rawQuery("select * from song where song_title like '" + selectionArgs[0] + "%'", null); 2 cursor.moveToFirst(); 3 System.out.println(cursor.getString(0));
關(guān)鍵就是這句 cursor.moveToFirst();
當(dāng)然使用 cursor.getString(0); 方法之后cursor并不會(huì)moveToNext
而對(duì)于SimpleCursorAdapter而言,則不需先進(jìn)行cursor.moveToFirst();
3、SimpleCursorAdapter的 _id 陷阱
使用SimpleCursorAdapter封裝Cursor時(shí)要求底層數(shù)據(jù)表的主鍵列的列名為_(kāi)id,因?yàn)镾impleCursorAdapter只能識(shí)別列名為_(kāi)id的主鍵
以下代碼會(huì)報(bào)錯(cuò) java.lang.IllegalArgumentException: column ‘_id’ does not exist
- cursor = db.rawQuery("select song_singer from song where song_singer like '"+selectionArgs[0]+"%' group by song_singer", null); 2 SimpleCursorAdapter simple_adapter = new SimpleCursorAdapter( 3 MusicLookup.this , R.layout.music_lookup_singer_item, cursor 4 , new String[]{"song_singer"} 5 , new int[]{R.id.song_singer_lookup_singer});
解決方法:
- cursor = db.rawQuery("select * from song where song_singer like '"+selectionArgs[0]+"%' group by song_singer", null); 2 SimpleCursorAdapter simple_adapter = new SimpleCursorAdapter( 3 MusicLookup.this , R.layout.music_lookup_singer_item, cursor 4 , new String[]{"song_singer"} 5 , new int[]{R.id.song_singer_lookup_singer});
要使用SimpleCursorAdapter,則不要在SQL語(yǔ)句中進(jìn)行column的選擇,而是在 new SimpleCursorAdapter(...) 的時(shí)候進(jìn)行對(duì)需要的column的選擇
4、關(guān)于 AutoCompleteTextView 與 SQLite 關(guān)聯(lián)數(shù)據(jù)源的陷阱
AutoCompleteTextView的使用需要ArrayAdapter 適配器來(lái)提供數(shù)據(jù)源,一般都使用 new ArrayAdapter
- private String[] test = {"a","ab","abc"};
這樣便不會(huì)引起 “元素?cái)?shù)<數(shù)組長(zhǎng)度” 的問(wèn)題,然而如果像下面這樣:
- private String[] test = new String[100]; 2 ...... 3 test[0] = "a"; 4 test[1] = "ab"; 5 test[2] = "abc"; 6 ......
這就會(huì)引起 “元素?cái)?shù)<數(shù)組長(zhǎng)度” 的問(wèn)題,雖然不會(huì)報(bào)錯(cuò),但使用
ArrayAdapter
來(lái)初始化ArrayAdapter,并把ArrayAdapter和AutoCompleteTextView關(guān)聯(lián)后,你會(huì)發(fā)現(xiàn),你輸入時(shí)并不會(huì)有自動(dòng)匹配。
從SQLite得來(lái)的數(shù)據(jù)是動(dòng)態(tài)的,是不能對(duì)字符串對(duì)象數(shù)組進(jìn)行事先的靜態(tài)初始化的,為了解決這個(gè)問(wèn)題,我使用了一下方法:
- private String[] str_ge_ming_auto; //聲明時(shí)先不初始化 ...... 2 try{ 3 cursor = db.rawQuery("select song_title from song", null); 4 cursor.moveToFirst(); 5 System.out.println("cursor.getCount() is "+cursor.getCount()); 6 str_ge_ming_auto = new String[cursor.getCount()]; //利用從SQLite返回的Cursor對(duì)象的getCount()方法得到需要的數(shù)組長(zhǎng)度 7 for ( int i= 0; i
- + "song_title varchar(20)," + "song_singer varchar(10)," + "song_info varchar(20));"); 18 }
當(dāng)前標(biāo)題:SQLite在Android中使用注意事項(xiàng)
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