日本综合一区二区|亚洲中文天堂综合|日韩欧美自拍一区|男女精品天堂一区|欧美自拍第6页亚洲成人精品一区|亚洲黄色天堂一区二区成人|超碰91偷拍第一页|日韩av夜夜嗨中文字幕|久久蜜综合视频官网|精美人妻一区二区三区

創(chuàng)新互聯(lián)python教程：

目前創(chuàng)新互聯(lián)公司已為千余家的企業(yè)提供了網(wǎng)站建設(shè)、域名、網(wǎng)站空間、網(wǎng)站托管維護(hù)、企業(yè)網(wǎng)站設(shè)計(jì)、尤溪網(wǎng)站維護(hù)等服務(wù)，公司將堅(jiān)持客戶導(dǎo)向、應(yīng)用為本的策略，正道將秉承"和諧、參與、激情"的文化，與客戶和合作伙伴齊心協(xié)力一起成長，共同發(fā)展。

編寫一個(gè) Python 程序來檢查一個(gè)數(shù)字是不是一個(gè) diarium 數(shù)字，或者是否使用 while 循環(huán)。如果一個(gè)給定數(shù)的數(shù)字加到其各自位置的冪的和等于實(shí)際數(shù)，它就是一個(gè) diarium 數(shù)字。例如，175 = 11 + 72 + 53 = 1 + 49 + 125 = 175。

在這個(gè) Python 程序中，我們將數(shù)字分成單個(gè)數(shù)字，并求出總和。接下來，if 語句檢查總和是否等于實(shí)際數(shù)字。如果是真的，這是一個(gè)災(zāi)難性的數(shù)字。

Number = int(input("Enter the Number to Check Disarium Number = "))
length = len(str(Number))

Temp = Number
Sum = 0
rem = 0

while Temp > 0:
    rem = Temp % 10
    Sum = Sum + int(rem**length)
    Temp = Temp // 10
    length = length - 1

print("The Sum of the Digits = %d" %Sum)

if Sum == Number:
    print("\n%d is a Disarium Number." %Number)
else:
    print("%d is Not a Disarium Number." %Number)

在這個(gè) Python 例子中，我們使用了 digitsCount 和 digitsSum 來檢查這個(gè)數(shù)字是否是一個(gè)異數(shù)。

import math

def digitsCount(Number):
    length = 0
    while Number != 0:
        length = length + 1
        Number = Number // 10
    return length

def digitsSum(Number, length):
    Sum = 0
    rem = 0

    while Number > 0:
        rem = Number % 10
        Sum = Sum + math.pow(rem, length)
        Number = Number // 10
        length = length - 1
    return Sum

Number = int(input("Enter the Number to Check Disarium Number = "))
length = digitsCount(Number)
Sum = digitsSum(Number, length)

print("The Sum of the Digits     = %d" %Sum)

if Sum == Number:
    print("%d is a Disarium Number." %Number)
else:
    print("%d is Not a Disarium Number." %Number)

Enter the Number to Check Disarium Number = 175
The Sum of the Digits     = 175
175 is a Disarium Number.

Enter the Number to Check Disarium Number = 24
The Sum of the Digits     = 18
24 is Not a Disarium Number.

Python 程序檢查一個(gè)數(shù)字是不是一個(gè) diarium 數(shù)字或者沒有使用遞歸。

import math

length = 0
Sum = 0

def digitsCount(Number):
    global length
    if Number > 0:
        length = length + 1
        digitsCount(Number // 10)
    return length

def digitsSum(Number, length):
    global Sum
    if Number > 0:
        rem = Number % 10
        Sum = Sum + math.pow(rem, length)
        digitsSum(Number // 10, length = length - 1)
    return Sum

Number = int(input("Enter the Number to Check Disarium Number = "))
length = digitsCount(Number)
Sum = digitsSum(Number, length)

print("The Sum of the Digits     = %d" %Sum)

if Sum == Number:
    print("\n%d is a Disarium Number." %Number)
else:
    print("%d is Not a Disarium Number." %Number)

Enter the Number to Check Disarium Number = 98
The Sum of the Digits     = 73
98 is Not a Disarium Number.

Enter the Number to Check Disarium Number = 135
The Sum of the Digits     = 135

135 is a Disarium Number.

本文標(biāo)題：Python程序：檢查數(shù)字是否是diarium數(shù)字
本文來源：http://www.dlmjj.cn/article/codghhe.html